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the magnitude of the electric field (E) produced by a point charge with a charge of magnitude Q, at a point a distance r away from the point charge, is given by the equation E = kQ/r2, where k is a constant with a value of 8.99 x 109 N m2/C2.

## What is the magnitude of the electric field E at a field point 2.0 m from a point charge q 4.0 NC?

Answer Expert Verified

The magnitude of the electric field is **9 N/C**.

## What is the magnitude of the electric field at a field point 2.0 m?

What is the magnitude of the electric field at a field point 2.0 m from a point charge 4.0 NC? Answer Expert Verified The magnitude of the electric field is **9 N/C**.

## What is the equation for electric field strength?

The strength of an electric field E at any point may be defined as the electric, or Coulomb, force F exerted per unit positive electric charge q at that point, or simply **E = F/q.**

## How do you solve for the magnitude of an electric field?

the magnitude of the electric field (E) produced by a point charge with a charge of magnitude Q, at a point a distance r away from the point charge, is given by the equation **E = kQ/r ^{2}**, where k is a constant with a value of 8.99 x 10

^{9}N m

^{2}/C

^{2}.

## What is the magnitude of the electric field?

The magnitude of the electric field is simply defined as **the force per charge on the test charge**. The standard metric units on electric field strength arise from its definition. Since electric field is defined as a force per charge, its units would be force units divided by charge units.

## What happens to the electric field when you measure it two times closer to the charge?

**The size of the force varies inversely as** the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value. … The size of the force is proportional to the value of each charge.

## What is the electric field due to a point charge of 2.00 nC nano coulombs at a distance of 5.00 mm from the charge?

Calculate the strength and direction of the electric field E due to a point charge of 2.00 nC (nano-Coulombs) at a distance of 5.00 mm from the charge. We can find the electric field created by a point charge by using the equation **E=kQ/r2 E = k Q / r 2 .** EkQr2(8.99×109N⋅m2/C2)×(2.00×10−9C)(5.00×10−3m)27.19×105N/C.