# You asked: What is the magnitude of the electric field at a field point?

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the magnitude of the electric field (E) produced by a point charge with a charge of magnitude Q, at a point a distance r away from the point charge, is given by the equation E = kQ/r2, where k is a constant with a value of 8.99 x 109 N m2/C2.

## What is the magnitude of the electric field E at a field point 2.0 m from a point charge q 4.0 NC?

The magnitude of the electric field is 9 N/C.

## What is the magnitude of the electric field at a field point 2.0 m?

What is the magnitude of the electric field at a field point 2.0 m from a point charge 4.0 NC? Answer Expert Verified The magnitude of the electric field is 9 N/C.

## What is the equation for electric field strength?

The strength of an electric field E at any point may be defined as the electric, or Coulomb, force F exerted per unit positive electric charge q at that point, or simply E = F/q.

## How do you solve for the magnitude of an electric field?

the magnitude of the electric field (E) produced by a point charge with a charge of magnitude Q, at a point a distance r away from the point charge, is given by the equation E = kQ/r2, where k is a constant with a value of 8.99 x 109 N m2/C2.

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## What is the magnitude of the electric field?

The magnitude of the electric field is simply defined as the force per charge on the test charge. The standard metric units on electric field strength arise from its definition. Since electric field is defined as a force per charge, its units would be force units divided by charge units.

## What happens to the electric field when you measure it two times closer to the charge?

The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value. … The size of the force is proportional to the value of each charge.

## What is the electric field due to a point charge of 2.00 nC nano coulombs at a distance of 5.00 mm from the charge?

Calculate the strength and direction of the electric field E due to a point charge of 2.00 nC (nano-Coulombs) at a distance of 5.00 mm from the charge. We can find the electric field created by a point charge by using the equation E=kQ/r2 E = k Q / r 2 . EkQr2(8.99×109N⋅m2/C2)×(2.00×10−9C)(5.00×10−3m)27.19×105N/C.